m^2=1600

Solution for m^2=1600 equation:

m^2=1600

We move all terms to the left:

m^2-(1600)=0

a = 1; b = 0; c = -1600;
Δ = b2-4ac
Δ = 02-4·1·(-1600)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*1}=\frac{-80}{2}
=-40
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*1}=\frac{80}{2}
=40
$